Question

Find the radius of $2^{nd}$ and $3^{rd}$ Bohr orbit of the hydrogen atom.

[$m=9.1\times {10}^{31}Kg$, $e=1.6\times {10}^{19}C]$

Answer 1

Radius of Bohr orbit, r$=\frac{n^2{h}^2}{4{\pi }^{2}m{e}^2}$

$=0.529\times \frac{n^2}{z}\mathring{A}$

Radius of $2^{nd}$ Bohr orbit means $n=2$

$=0.529\times \frac{2^2}{1}=2.116\mathring{A}$

Radius of $3^{rd}$ Bohr orbit means $n=3$

$=0.529\times \frac{3^2}{1}=4.761\mathring{A}$