Find the radius of a circle whose diameter has end points $(- 3, - 2)$ and $(7, 8)$ .

5

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5 \sqrt{2}

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(2, 3)

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\sqrt{52}

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none of these

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Solution

The correct option is E none of these
The length of diameter $= \sqrt{(- 3 - 7)^{2} + (- 2 - 8)^{2}} = \sqrt{100 + 100} = 10 \sqrt{2}$
$∴ r a d i u s = \frac{10 \sqrt{2}}{2} = 5 \sqrt{2}$
Option B is correct.

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