Find the radius of circle $x^{2} + y^{2} - 2 x - 8 y + 13 = 0$ .

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2$
Given circle is $x^{2} + y^{2} - 2 x - 8 y + 13 = 0$
The radius of circle is $\sqrt{g^{2} + f^{2} - c} \sqrt{1 + 16 - 13} \sqrt{4} = 2$

Suggest Corrections

Similar questions

x^{2} + y^{2} + 2 x + 8 y + 8 = 0

x^{2} + y^{2} - 6 x - 8 y = 0

Circles $x^{2} + y^{2} - 2 x - 4 y = 0 a n d x^{2} + y^{2} - 8 y - 4 = 0$

x^{2} + y^{2} - 6 x - 2 y + 1 = 0

x^{2} + y^{2} + 2 x - 8 y + 13 = 0

x^{2} + y^{2} - 2 x - 4 y = 0

x^{2} + y^{2} - 8 y - 4 = 0

Join BYJU'S Learning Program