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Question

# Find the radius of gyration of a uniform circular disc of radius R=1 m and mass M=2 kg about its axis passing through the edge and normal to the disc as shown in figure.

A
12 m
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B
52 m
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C
1 m
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D
32 m
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Solution

## The correct option is D √32 mGiven: Mass of disc M=2 kg Radius of disc R=1 m As we know, for circular disc Icom=MR22 Using parallel axes theorem, I=Icom+Md2 ∵ Here, d=R =MR22+MR2 I=32MR2 We know, Radius of gyration K=√IM= ⎷32MR2M=√32×R ⇒K=√32×1 m ⇒K=√32 m So, radius of gyration of a uniform disc about its axis passing through the edge and normal to the disc is √32 m.

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