Find the radius of the circle which passes through the origin ( 0 , 4) and (4 , 0)

\sqrt{8}

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\sqrt{32}

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Solution

The correct option is D $\sqrt{32}$
Centre of the circle $O = (0, 4)$
So, radius of the circle will be the distance between the centre and one of the point is passes through, which is $(4, 0)$
Distance between two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ is $\sqrt{{(x_{2} - x_{1})}^{2} + {{(y}_{2} - y_{1})}^{2}}$
So, distance between $(0, 4); (4, 0))$ is $\sqrt{{(4 - 0)}^{2} + {(0 - 4)}^{2}} = \sqrt{16 + 16} = \sqrt{32}$

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