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Question

Find the range of the following function given by
(i)f(x)=32x2
(ii)f(x)=1|x2|

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Solution

Range of i) 32x2 Range is R because when
x22+f(x)=2x22f(x)=
ii) f(x)=1|x2|
1 positive
Range is (,1]

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