Question

Find the range of the following functions
$f\left(x\right)=\frac{x^2-4}{x-2}$

Answer 1

$f\left(x\right)=\frac{x^2-4}{x-2}=\frac{(x+2)(x-2)}{(x-2)}=x+2,x\ne 2$

$\therefore Range=R-\left\{4\right\}$