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Question

Find the range of values of a for which the functionf(x)=x3+(2a+3)x2+3(2a+1)x+5 is monotonic in R Hence find the set of values of a for which f(x) in invertible.

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Solution

F(x) is monotonic in R
That implies f'(x) is either positive or negative for R (may be zero at a specific point)
f(x)=3x2+2(2a+3)x+3(2a+1)0
D0
(2a+3)29(2a+1)0
Solving we get a[0,32]

And since f(x) is a cubic polynomial it is onto function .
Thus it is invertible for a[0,32]

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