CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the range of values of a for which the functionf(x)=x3+(2a+3)x2+3(2a+1)x+5 is monotonic in R Hence find the set of values of a for which f(x) in invertible.

Open in App
Solution

F(x) is monotonic in R
That implies f'(x) is either positive or negative for R (may be zero at a specific point)
f(x)=3x2+2(2a+3)x+3(2a+1)0
D0
(2a+3)29(2a+1)0
Solving we get a[0,32]

And since f(x) is a cubic polynomial it is onto function .
Thus it is invertible for a[0,32]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Definition of Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon