Find the range of values of ′a′ for which the functionf(x)=x3+(2a+3)x2+3(2a+1)x+5 is monotonic in R Hence find the set of values of ′a′ for which f(x) in invertible.
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Solution
F(x) is monotonic in R
That implies f'(x) is either positive or negative for R (may be zero at a specific point)
f′(x)=3x2+2(2a+3)x+3(2a+1)≥0
→D≤0
→(2a+3)2−9(2a+1)≤0
Solving we get a∈[0,32]
And since f(x) is a cubic polynomial it is onto function .