MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Quantitative Aptitude

Solving Inequalities

Find the rang...

Question

Find the range of $x^{2} + 6 x + 5$

Open in App

Solution

$f (x) = x + 6 x + 5 = (x - 3) + 14 - (x - 3) \leq 0$ , for all x real.Add 14 to both sides of the inequality $(x - 3) + 14 \leq 14$ . The left side is the given function. Hence the range is given by the interval $(- \infty, 14)$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Find the range of

y = \frac{x^{2} - 2}{x^{2} + 5}

Q. What is the range of

f (x) = \frac{1}{x^{2} + 6 x + 6}

Q. Find the range of

f (x) = \sqrt{1 - \sqrt{x^{2} - 6 x + 9}}

Q. Find the range Of f(x)=(1-(x²-6x+9)^1/2)^1/2

Q. Find the range of each of the following functions

f (x) = x^{2} - 6 x + 11

x \in R

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Inequations II

QUANTITATIVE APTITUDE

Watch in App

explore_more_icon

Explore more

Solving Inequalities

Other Quantitative Aptitude

Join BYJU'S Learning Program

CrossIcon