find the range of y={x}/1+{x

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y = \frac{e^{- x}}{1 + [x]}

y = \frac{x}{1 + | x |}

y = \frac{x^{2} - x + 1}{x^{2} + x + 1}

If x is real, find the range of y from the equation $x^{2} (y - 1) - 2 x + (2 y - 1)$ = 0

y = \sqrt{x - 1}

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