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Question

Find the rate of heat flow through a cross-section of the tapered conical rod shown in figure (Temperature of the big end(θ2)> Temperature of the small end(θ1)), with radius r1 and r2 at the small and big end respectively. Thermal conductivity of the material of the rod is K.


A

Kπr21r22(θ2θ1)L3

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B

Kπr1r2(θ2θ1)L

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C

Kπr31r32(θ2θ1)L5

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D

Kπr1r2l(θ2θ1)

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Solution

The correct option is B

Kπr1r2(θ2θ1)L


As is evident the cross sectional area is not constant, it varies with x and the corresponding radius r

By the fact that the slope of the line is constant

r2r1l=rr1x

r=(r2r1l)x+r1 ..........(i)

Now, consider a cylindrical shell with infinitesimal thickness dx, let dθ be the temperature difference

ΔQΔt=KAdθdx=Kπr2dθdx ......(ii)

From (i) and (ii)

ΔQΔt=Kπ[(r2r1l)x+r1]2dθdx

ΔQΔtL0dx(r1+(r2r1L)x)2=Kπθθ1dθ ..(iii)

Let , y=r1+(r2r1l)x

Lθdx(r1+(r2r1L)x)2=lr2r1r2r1dyy2

=lr2r1×(lr1lr2)

=lr1r2

From (iii) and (iv)

ΔQΔt=Kπr1r2(θ2θ1)l


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