Find the rate of interest when Rs. $800$ fetches Rs. $130$ as simple interest in $2$ years $6$ months.

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Solution

$S . I = R s 130$
$T = 2 y e a r s 6 m o n t h s = 2 + \frac{1}{2} = \frac{5}{2} y e a r s$
$Principle = 800 rupees$
$Rate = ?$
$S . I = \frac{P \times R \times T}{100}$
$130 = \frac{800 \times R \times \frac{5}{2}}{100}$
$\frac{130}{5} = 4 R$
$4 R = \frac{130}{5}$
$R = \frac{130}{20}$
$R = 6.5 % p e r a n n u m$

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Find the rate of interest when Rs. 800 fetches Rs. 130 as simple interest in 2 years 6 months.

S.I=Rs130T=2years6months=2+12=52yearsPrinciple = 800rupeesRate = ?S.I=P×R×T100130=800×R×521001305=4R4R=1305R=13020R=6.5%perannum

Find the rate of interest when Rs. $800$ fetches Rs. $130$ as simple interest in $2$ years $6$ months.