Find the ratio AC/BC for the following construction method.
A ray AX is extended from A and 13 arcs of equal lengths are cut, cutting the ray at A1, A2… A13.
Another ray parallel to AX is extended from B and 2 arcs of equal lengths are cut, cutting the ray at B1 and B2. Line joining A13 and B2 cuts AB at C.
13:2
In the construction process given, triangles △AA13C and △BB2C are similar.
So, ACBC = AA13BB5
By construction, AA13BB5 = 132.
Therefore, AC:BC= 13:2.