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Question

Find the ratio AC/BC for the following construction method.
A ray AX is extended from A and 13 arcs of equal lengths are cut, cutting the ray at A1, A2… A13.
Another ray parallel to AX is extended from B and 2 arcs of equal lengths are cut, cutting the ray at B1 and B2. Line joining A13 and B2 cuts AB at C.


A

13:15

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B

13:2

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C

15:2

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D

None of these

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Solution

The correct option is B

13:2


In the construction process given, triangles AA13C and BB2C are similar.

So, ACBC = AA13BB5

By construction, AA13BB5 = 132.

Therefore, AC:BC= 13:2.


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