Find the ratio between one side of the triangle in the photograph to one side of the triangle in the actual drawing.

1 i n : 50 f t

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1 i n : 15 f t

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15 i n : 1 f t

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1 i n : 75 f t

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Solution

The correct option is A $1 i n : 50 f t$

Length of one side of traingle in actual drawing = 750 ft.
Length of one side of triangle in photograph = 15 in.

∴ Length of one side of traingle which is 1 inch in photograph is:

$\frac{750 \times 1}{15} = 50 f t .$

So, the scale is:
$1 i n : 50 f t$

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Find the ratio between one side of the triangle in the photograph to one side of the triangle in the actual drawing.

The correct option is A 1 in : 50 ft Length of one side of traingle in actual drawing = 750 ft. Length of one side of triangle in photograph = 15 in. ∴ Length of one side of traingle which is 1 inch in photograph is: 750×115=50 ft . So, the scale is: 1 in : 50 ft

The correct option is A $1 i n : 50 f t$

Length of one side of traingle in actual drawing = 750 ft.
Length of one side of triangle in photograph = 15 in.

∴ Length of one side of traingle which is 1 inch in photograph is:

$\frac{750 \times 1}{15} = 50 f t .$

So, the scale is:
$1 i n : 50 f t$