Find the ratio by mass of the combining elements in carbon monoxide.

C O_{2}

: 3 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C O_{2}

: 4 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C O

: 3 : 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C O

: 4 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C O$ : 3 : 4
In carbon monoxide, CO, atomic mass of carbon is $12$ and that of oxygen is $16$ .
$∴$ C : O
$= 12 : 16$
$= 3 : 4$

Suggest Corrections

Similar questions

O_{2}

C O_{2}

{cos}^{4} (π / 8) + {cos}^{4} (3 π / 8) + {cos}^{4} (5 π / 8) + {cos}^{4} (7 π / 8) - 3 / 2

{({N H}_{4})}_{2} {C O}_{3}

1

C l O_{4}^{-}

2

B F_{3}

3

S O_{4}^{2 -}

4

C O_{3}^{2 -}

The volume of gases $N H_{3}$ , $C O_{2}$ and $C H_{4}$ adsorbed by one gram of charcoal at 298 K are in

Join BYJU'S Learning Program