Find the ratio by mass of the combining elements in the $C_{2} H_{5} O H$ .

1 : 3 : 8

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12 : 13 : 8

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12 : 3 : 8

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none of these

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Solution

The correct option is C $12 : 3 : 8$
$C_{2} H_{5} O H$
$\Rightarrow C \times 2 : H \times 6 : O$
$\Rightarrow 12 \times 2 : 1 \times 6 : 16$
$\Rightarrow 24 : 6 : 16$
$\Rightarrow 12 : 3 : 8$

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Similar questions

Find the ratio by mass of the combining elements in the compound - $C_{2} H_{5} O H$ .

Q. Which of the following is correct with respect to the mass ratio of the combining elements in the compound -

C_{2} H_{5} O H

Verify each of the following :

(i) $\frac{3}{7} \times \frac{- 5}{9} = \frac{- 5}{9} \times \frac{3}{7}$

(ii) $\frac{- 8}{7} \times \frac{13}{9} = \frac{13}{9} \times \frac{- 8}{7}$

(iii) $\frac{- 12}{5} \times \frac{7}{- 36} = \frac{7}{- 36} \times \frac{- 12}{5}$

(iv) $- 8 \times \frac{- 13}{12} = \frac{- 13}{12} \times (- 8)$

Q. Name the property of rational numbers illustrated by the given statement.

\frac{7}{4} \times (\frac{- 8}{3} + \frac{- 13}{12}) = \frac{7}{4} \times \frac{- 8}{3} + \frac{7}{4} \times \frac{- 13}{12}

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

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Find the ratio by mass of the combining elements in the C2H5OH.

The correct option is C 12:3:8C2H5OH⇒C×2:H×6:O⇒12×2:1×6:16⇒24:6:16⇒12:3:8

Find the ratio by mass of the combining elements in the $C_{2} H_{5} O H$ .

The correct option is C $12 : 3 : 8$
$C_{2} H_{5} O H$
$\Rightarrow C \times 2 : H \times 6 : O$
$\Rightarrow 12 \times 2 : 1 \times 6 : 16$
$\Rightarrow 24 : 6 : 16$
$\Rightarrow 12 : 3 : 8$