Find the ratio by mass of the combining elements in the $H_{2} S O_{4}$ .

1 : 16 : 32

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15 : 16 : 32

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1 : 16 : 16

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none of these

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Solution

The correct option is A $1 : 16 : 32$
$H_{2} S O_{4}$
$\Rightarrow H \times 2 : S : O \times 4$
$\Rightarrow 1 \times 2 : 32 : 16 \times 4$
$\Rightarrow 2 : 32 : 64$
$\Rightarrow 1 : 16 : 32$

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H_{2} S O_{4}

H = 1, S = 32, O = 16

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2^{\frac{1}{4}} {.4}^{\frac{1}{8}} {.8}^{\frac{1}{16}} . 16^{\frac{1}{32}} . . . . . . . . . . . . . . . = 32^{\frac{1}{m}}

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