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Standard XII

Physics

Nucleus: Common Terms

Find the rati...

Question

Find the ratio by mass of the constituent of $C a (O H)_{2}$ .

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Solution

$C a (O H)_{2}$
$\Rightarrow C a : O \times 2 : H \times 2$
$\Rightarrow 40 : 16 \times 21 \times 2$
$\Rightarrow 40 : 32 : 2$
$\Rightarrow 20 : 16 : 1$

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Question 25
Find the ratio by mass of the combining elements in the following compounds.

(a) $C a C O_{3}$ (d) $C_{2} H_{5} O H$

(b) $M g C l_{2}$ (e) $N H_{3}$

(c) $H_{2} S O_{4}$ (f) $C a (O H)_{2}$

Q. Find the ratio by mass of the combining elements in the following compounds.

(a)

C a C O_{3}

(d)

C_{2} H_{5} O H

(b)

M g C l_{2}

(e)

N H_{3}

(c)

H_{2} S O_{4}

(f)

C a (O H)_{2}

Two samples 'm' and 'n' of slaked lime,

C a (O H)_{2}

, were obtained from two different reactions. The details about their composition are as follows:

S a m p l e^{'} m^{'} - ----------- -

Total mass: 7 g

Mass of constituent oxygen: 2 g

Mass of constituent calcium: 5 g

S a m p l e^{'} n^{'} - ---------- -

Total mass: 1.4 g

Mass of constituent oxygen: 0.4 g

Mass of constituent calcium: 1 g

Which law of chemical combination does this prove? Explain.

Question 25
Find the ratio by mass of the combining elements in the following compounds.

(a) $C a C O_{3}$ (d) $C_{2} H_{5} O H$

(b) $M g C l_{2}$ (e) $N H_{3}$

(c) $H_{2} S O_{4}$ (f) $C a (O H)_{2}$

Two samples ‘m’ and ‘n’ of slaked lime were obtained from two different reactions. The details about their composition are as follows:

‘sample m’ mass : 7g

Mass of constituent oxygen : 2g

Mass of constituent calcium : 5g

‘sample n’ mass : 1.4g

Mass of constituent oxygen : 0.4g

Mass of constituent calcium : 1.0g

Which law of chemical combination does this prove? Explain.

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Find the ratio by mass of the constituent of Ca(OH)2.

Ca(OH)2⇒Ca:O×2:H×2⇒40:16×21×2⇒40:32:2⇒20:16:1

Find the ratio by mass of the constituent of $C a (O H)_{2}$ .

$C a (O H)_{2}$
$\Rightarrow C a : O \times 2 : H \times 2$
$\Rightarrow 40 : 16 \times 21 \times 2$
$\Rightarrow 40 : 32 : 2$
$\Rightarrow 20 : 16 : 1$