Question

Find the ratio in which the line joining the points $(-3,3)$ and $(2,6)$ is divided by the y-axis.

• A. $1:3$
• B. $3:2$
• C. $2:1$
• D. $1:2$

Answer 1

The correct option is B $3:2$

Let $(-3,3)$ and $(2,6)$ be divided by the $y-$axis in the ratio $k:1$

$\Rightarrow x=0$

Using Section formula:$(x,y)=(\frac{m{x}_2+n{x}_1}{m+n},\frac{m{y}_2+n{y}_1}{m+n})$ we have

$(0,y)=(\frac{2k-3}{k+1},\frac{6k+3}{k+1})$

$\Rightarrow \frac{2k-3}{k+1}=0$

$\Rightarrow 2k=3$

or $k=\frac{3}{2}$

Thus, the ratio is $3:2$