Question

Find the ratio in which the line segment joining A(2,-2)and B(-3,-5) is divided by the y axis.

• A. 2 : 3
• B. 3 : 2
• C. 4 : 9
• D. 6 : 8

Answer 1

The correct option is A 2 : 3

A point on y - axis is (0, y)
Let this point divide A(2,-2)and B(-3,-5) points are in the ratio k : 1
The coordinates of P (0, y) are
$p(0,y)=(\frac{1\times 2+k\times -3}{k+1},\frac{1\times -2+k\times -5}{k+1})$
$=\frac{2-3k}{k+1},\frac{-2-5k}{k+1}$

$\Rightarrow \frac{2-3k}{k+1}=0$

$\Rightarrow 2-3k=0$
$\Rightarrow k=\frac{2}{3}$

Hence, k : 1 = m : n = $\frac{2}{3}$ : 1
= 2 : 3


Therefore, the ratio in which y axis divides AB is 2 : 3