Find the ratio in which YZ-plane divides the line segment joining $A (2, 4, 5)$ and $B (3, 6, - 4)$ .

- 2 : 3

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2 : 3

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3 : 2

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- 3 : 2

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Solution

The correct option is A $- 2 : 3$
$a n y p o i n t o n Y Z p l a n e w i l l h a v e x - c o o r d i n a t e t o b e z e r o . l e t t h e r a t i o o f d i v i s i o n b e k! 1, t h e n (\frac{3 k + 2}{k + 1}) = 0 ∴ k = (\frac{- 2}{3})$

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y z

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B (3, 5, - 4)

- 2 : 3

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