Question

Find the ratio of area to the perimeter of an obtuse angle triangle as shown in the figure below.

• A. $\frac{24}{25}$
• B. $\frac{24}{25}unit$
• C. $\frac{25}{24}unit$
• D. $\frac{30}{25}$

Answer 1

The correct option is B $\frac{24}{25}unit$

Given,
Base of a triangle$=BC=8$
Height of a triangle$=AD=6$

As we know,
$\text{Area of}△ABC=\frac{1}{2}\times \text{Base}\times \text{Height}$

$=\frac{1}{2}\times 8\times 6$

$=24sq.unit.$

Perimeter of the triangle = Sum of all three sides of a traingle.
$=AB+BC+AC$

$=7+8+10=25$ unit.

Hence the ratio is,
$\frac{\text{Area of a triangle ABC}}{\text{Perimeter of a triangle ABC}}=\frac{24}{25}unit$.

Option (b) is correct.