Find the ratio of molar amounts of H2s needed to precipitise metal ions from. 20 ml each of 1 M CD(NO3)2 and 0.5 M.CuSO4?

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Solution

Dear Student,

Chemical reactions:

1) $H_{2} S + C d (N O_{3})_{2} \to C d S + 2 H N O_{3} m o l e s 1 1 1 2$

Moles of Cd(NO₃)₂= $\frac{1}{1000} \times 20 = 0.02 m o l e$
Hence, according to the above reaction, moles of H₂S needed = 0.02 moles

2) $H_{2} S + C u S O_{4} \to C u S + H_{2} S O_{4} m o l e s 1 1 1 1$

Moles of CuSO₄= $\frac{0.5}{1000} \times 20 = 0.01 m o l e$
Hence, according to the above reaction, moles of H₂S needed = 0.01 moles

Therefore, the ratio of molar amount of H₂S needed will be = 0.02 : 0.01 = 2 : 1.

Best Wishes !

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