Question

Find the ratio of no. of pure and hybrid orbitals in benzene with clear explanation and structure.

Answer 1

The structure of benzene is following:

The $\pi$ bonds are formed using pure p-orbitals.

$\therefore$ No. of pure p-orbitals = 6

Because, 2 pure p-orbitals lead to formation of 1$\pi$ bond.

No. of hybridised orbitals = $6\times 3=18$

Because each carbon is $s{p}^2$ hybridised i.e., it uses 3 hybridised orbitals.

Therefore, ration of pure p-orbitals to the hybrid orbitals is 6 : 18 that is 1 : 3.