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Liquid Pressure

Find the rati...

Question

Find the ratio of pressures experienced by the divers. Assume the density of seawater is $1000 {kg/m}^{3}$ and the acceleration due to gravity ( $g = 10 {m/s}^{2}$ ) remains constant throughout.

49 : 74

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2 : 3

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74 : 49

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1 : 1

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Solution

The correct option is B $2 : 3$

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Similar questions

7 MPa

g = 10 {m/s}^{2}

1000 {kg/m}^{3}

FIND THE NEW VALUE OF THE, ACCELERATION DUE TO GRAVITY IF THE RADIUS OF THE EARTH IS REDUCED BY 10%,WHHERE DENSITY OF EARTH REMAINS CONSTANT?

ρ_{w a t e r} = 1000 k g / m^{3}

g = 10 m / s^{2}

Calculate the pressure at a depth of $50 m$ below sea level.

Given:
Density of sea water = $1024 k g / m^{3}$ .
And, acceleration due to gravity $g = 10 m / s^{2}$

6.38 \times 10^{8} c m

6.67 \times 10^{-} 8 c m^{3} / g s^{2}

980 c m / s^{2}

- g / c m^{3}

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