Question

Find the ratio of the distance from the center of the circle to congruent sides of the triangles, if $△AEC\cong △DFB.$

• A. $1:1$
• B. $2:1$

Answer 1

The correct option is A $1:1$

Given: $△AEC\cong △DFB$
Let G is centre of the circle here.

$\therefore$ Vertex F corresponds to E and vertex B corresponds to C.
Congruent triangles have corresponding sides equal in length.

Hence, $FB=EC,AE=DF,AC=DB$.
Chords of equal length are equidistant from the center of the circle.

$\therefore$ The required ratio is $1:1.$