Question

Find the ratio of the electric and gravitational force between two protons.

Answer 1

Charge on proton $=1.6\times {10}^{-19}$
$\therefore F_{electrical}=\frac{1}{4\pi {ϵ}_0}\times \frac{q_q}{r^2}=\frac{9\times {10}^9\times (1.6{)}^2\times {10}^{-38}}{r^2}$
mass of proton $=1.732\times {10}^{-27}kg$
$F_{gravity}=G\frac{m_1{m}_2}{r^2}=\frac{6.67\times {10}^{-11}\times \left(1.732\right)\times {10}^{-54}}{r^2}$
$\dfrac{F_e}{F_g}=\dfrac{\dfrac{9\times 10^9\times (1.6)^2\times 10^{-38}}{r^2}}{\dfrac{6.67\times 10^{-11}\times (1.732)\times 10^{-54}}{r^2}}
=\dfrac{9\times (1.6)^2\times 10^{-29}}{6.67(1.732)^2 10^{-65}}=1.24\times 10^{36}$