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Question

Find the ratio of the magnitude of the electric force to the gravitational force acting between two protons

A
1030
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B
1032
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C
1034
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D
1036
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Solution

The correct option is D 1036
We know, Charge on one Proton = + 1.6 × 10⁻¹⁹ C.and Mass of the Proton = 1.6727 × 10⁻²⁷ kg.
Now, Using the Coulomb's Law,
F = (k q₁ q₂) ÷ r²
where,
k = 8.99 × 10⁹ Nm²kg⁻²
k ≈ 9 × 10⁹ Nm²kg⁻²
q₁ = q₂ = 1.6 × 10⁻¹⁹ C
r = Distance between the Two Protons.
Now,
F = 9 × 10⁹ × (1.6 × 10⁻¹⁹)² ÷ r²
⇒ F₁ = 23.04 × 10⁻²⁹/r² -----eq(i)
Now, Using Newton's law of Gravitation,
Here, G = Gravitation Constant whose value is 6.67 × 10⁻¹¹ Nm²kg⁻².
⇒ F r² = 6.67 × 10⁻¹¹ × (1.6727 × 10⁻²⁷)²
⇒ F₂ = 18.66 × 10⁻⁶⁵/r²
Now, Let us calculate the ratio of the Electrostatic Forces to the Gravitational Force between the Two Protons.
∴ F₁/F₂ = (23.04 × 10⁻²⁹/r²) ÷ (18.66 × 10⁻⁶⁵/r²)
⇒ F₁/F₂ = 1.24 × 10³⁶
Hence,
Option (D) is correct answer.



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