Question

Find the ratio of the total number of bonds to lone pair of $s{p}^2$-hybrid orbitals in $C_3{N}_3(N_3{)}_3.$

Answer 1

There are $15$ bonds and $3$ lone pairs of electrons.
Hence, the ratio of the total number of bonds to lone pair of $s{p}^2$-hybrid orbitals in $C_3{N}_3(N_3{)}_3$ is $\frac{15}{3}=5$