Find the ratio of trans-isomers in [M(AA)b2c2] and [Ma4b2], respectively.
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Solution
The ratio of trans-isomers in [M(AA)b2c2] and [Ma4b2], respectively is 2. [M(AA)b2c2] has 2 trans isomers and [Ma4b2] has 1 trans isomer. So the ratio is 21 = 2