wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the ratio of trans-isomers in [M(AA)b2c2] and [Ma4b2], respectively.

Open in App
Solution

The ratio of trans-isomers in [M(AA)b2c2] and [Ma4b2], respectively is 2.
[M(AA)b2c2] has 2 trans isomers and [Ma4b2] has 1 trans isomer.
So the ratio is 21 = 2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Structural Isomerism
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon