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Question

Find the ratio of trans-isomers in [M(AA)b2c2] and [Ma4b2], respectively.

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Solution

The ratio of trans-isomers in [M(AA)b2c2] and [Ma4b2], respectively is 2.
[M(AA)b2c2] has 2 trans isomers and [Ma4b2] has 1 trans isomer.
So the ratio is 21 = 2

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