Find the reading of machine. Given each box of mass $= 15 k g$ ,mass of man $1 = 30 k g$ , mass of man $2 = 40 k g$ and of each weighing machine $= 5 k g$

360 / 11 k g, 400 / 11 k g

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330 / 11 k g, 440 / 11 k g

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360 / 11 k g, 440 / 11 k g

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350 / 11 k g, 240 / 11 k g

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Solution

The correct option is B $360 / 11 k g, 400 / 11 k g$
$G i v e n :$ Each box of mass $= 15 k g$ ; mass of man $1 = 30 k g$ ; mass of man $2 = 40 k g$ ; each Weighing machine $= 5 k g$
$S o l u t i o n :$
$T - 50 g = 50 a . . . . (i)$
$60 g - T = 60 a . . . . (i i)$
$\Rightarrow 10 g = 110 a$
$\Rightarrow a = \frac{g}{11}$
$F o r (i)$
$R e a d i n g = m g + m a$
$= 30 g + \frac{30}{11} g$
$= \frac{360}{11} g$ .
In $k g = \frac{360}{11} k g$
$F o r (i i)$
$\Rightarrow m g - m a$
$= \frac{400}{11} k g$ .
$S o, t h e$ $c o r r e c t$ $o p t i o n : A$

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