Question

Find the reading of the ammeters $A_1$, (in ampere) connected as shown in the network.(Answer in integer value)

Answer 1

From the diagram, it is clearly evident that all the resistors are in parallel.


Therefore, Potential difference across each resistance is same.

So, the current passing through the resistance $12\Omega$ is $I_{12}=\frac{24}{12}=2\text{A}$.

Hence, the reading of ammeter is $2\text{A}$

Accepted answer: $2$