Find the reading of the spring balance considering spring, pulley and string to be massless.
A
600N
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B
300N
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C
200N
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D
400N
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Solution
The correct option is B300N The spring balance will read the tension in the string. Let the common acceleration is a. FBD of the two blocks and the spring balance,
On applying ∑F=ma on the two blocks and the spring, we get, 600−T1=60a .............(1) T1−T2=0 ............(2) T2−200=20a .............(3) On adding all the equations, we get, a=5m/s2, putting this in (1), we get, T1=300N T1=T2=300N [from (2)]