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Question

Find the reading of the spring balance considering spring, pulley and string to be massless.


A
600 N
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B
300 N
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C
200 N
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D
400 N
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Solution

The correct option is B 300 N
The spring balance will read the tension in the string. Let the common acceleration is a.
FBD of the two blocks and the spring balance,

On applying F=ma on the two blocks and the spring, we get,
600T1=60a .............(1)
T1T2=0 ............(2)
T2200=20a .............(3)
On adding all the equations, we get,
a=5 m/s2, putting this in (1), we get,
T1=300 N
T1=T2=300 N [from (2)]

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