Find the reading of the spring balance for the figure shown. Take g=10m/s2
A
1.2kg
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B
2.4kg
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C
3.6kg
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D
4.8kg
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Solution
The correct option is D4.8kg The given spring balance arrangement can be converted to string arrangement as shown
As we know that the spring balance reads the spring force kx which is equivalent to tension T in the string.
So, from the FBDs of both the blocks we have 6g−T=6a........(i)
and, T−4g=4a.......(ii)
On solving (i) & (ii), we get 2g=10a⇒a=2g10=2m/s2 ∴ from FBD of 6Kg we have T=6(g−a)=6×8=48N
So, the reading in spring balance is
Equivalent mass = 48g=4.8kg
Alternate:
a=supporting force- opposing forceTotal mass =6g−4g10=2g10=2m/s2
For 6kg mass ; T=6(g−a)=6×8=48N ∴ Equivalent mass = 48g=4.8kg