Find the reading of the spring balance if M is in equilibrium. Assume all surfaces to be smooth. Take g=10m/s2
A
1kg
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B
1.2kg
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C
1.4kg
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D
1.6kg
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Solution
The correct option is B1.2kg The FBDs of the system are as shown
As we know that the spring balance reads the value of spring force kx So, from the FBDs we have N=2.5gcos37∘ and, kx=Ncos53∘=(2.5gcos37∘).cos53∘ kx=2.5×10×45×35 kx=12N Thus, the equivalent mass shown by spring balance is 12g=1210=1.2kg