Find the reading of the spring balance shown in figure. The elevator is going up with an acceleration of g/10, the pulley and the string are light and the pulley is smooth.

4.4 kg

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5 kg

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10 kg

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49.5 N

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Solution

The correct option is
A

4.4 kg

Lets go to lift frame and observe.

Since it is a non-inertial frame so we have to consider a pseudo force.

Lets assume in lift's frame that 1.5 kg block is going up with acceleration a and 3 kg block is coming down with acceleration a.

From the FBD of 1.5 kg block we have,

$T - 1.5 g - \frac{1.5 g}{10} = 1.5 a$

$T - 16.5 = 1.5 a$ ............(I)

From the FBD of 3 kg block we have,

30 + 3 - T = 3a
33 - T = 3a.......................(II)
Solving (I) & (II) we get,
T = 22 N
Reading of spring balance = 2T = 44 N.
= 4.4 kg.

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