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Question
Find the real and imaginary parts of the complex number z=3i20−i192i−1
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Solution
z=3i20−i192i−1=3(1)−(−i)))2i−1=3+i−1+2i
=3+i−1+2i×−1−2i−1−2i
=−3−6i−i−2i2(−12)+22
=−1−7i5=−15−75i
Re(z)=−15 and Im(z)=−75
=3+i−1+2i×−1−2i−1−2i
=−3−6i−i−2i2(−12)+22
=−1−7i5=−15−75i
Re(z)=−15 and Im(z)=−75
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