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Question

Find the real numbers x and y if (xiy) (3 + 5i) is the conjugate of –6 – 24i.

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Solution

Let

It is given that,

Equating real and imaginary parts, we obtain

Multiplying equation (i) by 3 and equation (ii) by 5 and then adding them, we obtain

Putting the value of x in equation (i), we obtain

Thus, the values of x and y are 3 and –3 respectively.


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