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Question

Find the real numbers x and y if (xiy)(3+5i) is the conjugate of 624i.

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Solution

Given: (xiy)(3+5i)=624i
(x+iy)(35i)=624i
3x5xi+3yi+5y=624i
On compairing
3x+5y=6 __ (1)
5x+3y=24 __ (2)
Solve (1) and (2)
15x+25y=30
15x+9y=72
______________
16y=42
y=4216=21/8
3x+21×58=6x=(61058)×13
=1358×3=458
x=45/8y=21/8

1118845_1202355_ans_fdbae6b2cc71498998a5f6279f56423c.jpg

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