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Question

Find the real values of r which the following system of linear equations has a non-trivial solution. Also find the non-trivial solutions:
2rx2y+3z=0x+ry+2z=02x+rz=0

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Solution

=0r32r4=0(r2)(r2+2r+2)=0
r=2 as other factor gives imaginary roots. Putting r=2, the equation reduces to 4x2y+3z=0,x+2y+2z=0 and x+z=0
Putting x+z=0, they reduce to x2y=0,2y+z=0 and x+z=0.
Choosing x=k, we get y=k2,z=k which given the required solutions.

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