Find the reciprocal of - 122 - 143 - - 23

K=[(12^2) (14^3)]× 2^3 We need to find 1K. K=[(12^2) (12^2)^3]× 2^3 K=[2^32^2 2^32^6] K=158⇒1/k=8/15 ∴reciprocal of[(1/2)^2 (1/4) ...

1049

You visited us 1049 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Properties of GP

Find the reci...

Question

Find the reciprocal of $[{(\frac{1}{2})}^{2} - {(\frac{1}{4})}^{3}] \times 2^{3}$

Open in App

Solution

$K = [({\frac{1}{2}}^{2}) - ({\frac{1}{4}}^{3})] \times 2^{3}$
We need to find $\frac{1}{K} .$
$K = [({\frac{1}{2}}^{2}) - (\frac{1}{2^{2}})^{3}] \times 2^{3}$
$K = [\frac{2^{3}}{2^{2}} - \frac{2^{3}}{2^{6}}]$
$K = \frac{15}{8} \Rightarrow \frac{1}{k} = \frac{8}{15}$
$∴ r e c i p r o c a l o f [(\frac{1}{2})^{2} - (\frac{1}{4})^{3}] \times 2^{3} i s \frac{8}{15}$

Suggest Corrections

Similar questions

Q. Find the reciprocal of

\frac{2}{3} \div \frac{14}{15}

Find $(3^{3} - 2^{3}) + (5^{3} - 4^{3}) + (7^{3} - 6^{3}) + . . . .$ to 10 terms.

Show that $\frac{1 \times 2^{2} + 2 \times 3^{2} + . . . . + n \times (n + 1)^{2}}{1^{2} \times 2 + 2^{2} \times 3 + . . . . + n^{2} \times (n + 1)} = \frac{3 n + 5}{3 n + 1}$

Q. Rationales the denominator and simplify:

(i)

\frac{3 - \sqrt{2}}{3 + \sqrt{2}}

(ii)

\frac{5 + 2 \sqrt{3}}{7 + 4 \sqrt{3}}

(iii)

\frac{1 + \sqrt{2}}{3 - 2 \sqrt{2}}

(iv)

\frac{2 \sqrt{6} - \sqrt{5}}{3 \sqrt{5} - 2 \sqrt{6}}

(v)

\frac{4 \sqrt{3} + 5 \sqrt{2}}{\sqrt{48} + \sqrt{18}}

(vi)

\frac{2 \sqrt{3} - \sqrt{5}}{2 \sqrt{2} + 3 \sqrt{3}}

Find the reciprocal of the rational number ${(\frac{1}{2})}^{2} \div {(\frac{2}{3})}^{3} .$

1 + \frac{2^{3}}{2!} + \frac{3^{3}}{3!} + \frac{4^{3}}{4!} + . . . = c e

.
Find

c

Join BYJU'S Learning Program

Find the reciprocal of [(12)2−(14)3]×23

K=[(122)−(143)]×23We need to find 1K.K=[(122)−(122)3]×23K=[2322−2326]K=158⇒1k=815∴reciprocalof[(12)2−(14)3]×23is815

Find the reciprocal of $[{(\frac{1}{2})}^{2} - {(\frac{1}{4})}^{3}] \times 2^{3}$