Find the reciprocals-a 452n - 1b 25 - 3- 54 - 2

a) Reciprocal of ( 45)^2n 1 = 1( 45)^2n 1= ( 45)^ (2n 1)= ( 54)^2n 1 b) #160; #160; ( 25)^ 3×( 54)^ 2=1(2/5)^3×1(5/4)^2 ...

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Properties of GP

Find the reci...

Question

Find the reciprocals.
a) ${(\frac{4}{5})}^{2 n - 1}$
b) ${(\frac{2}{5})}^{- 3} \times {(\frac{5}{4})}^{- 2}$

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n

{(\frac{4}{5})}^{3} \times {(\frac{4}{5})}^{- 6} = {(\frac{4}{5})}^{2 n - 1}

$b)$

n (3^{- 5}) = 3

$c)$

n {(- 5)}^{4} \div n^{2} = 5

Find the mode from the given data.

1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4, 1, 2 , 3, 4, 1, 2, 3, 4, 1 ,2 , 3, 4, 5, 5, 1, 5, 5, 5, 3, 5, 1, 2, 4, 5, 6, 1, 2, 4, 2, 1

(1 \times 2) + (2 \times 3) = \frac{2 \times 3 \times 4}{3}

(1 \times 2) + (2 \times 3) + (3 \times 4) = \frac{3 \times 4 \times 5}{3}

(1 \times 2) + (2 \times 3) + (3 \times 4) + (4 \times 5) = \frac{4 \times 5 \times 6}{3}

\frac{2}{1!} + \frac{4}{3!} + \frac{6}{5!} + \frac{8}{7!} + . . . t o \infty = \frac{1}{\frac{2}{a!} + \frac{4}{5!} + \frac{6}{b!} + . . . t o \infty}

b - a

Find the value of 'n' such that

\frac{2}{3} (4 n - 1) - (2 n - \frac{1 + n}{3}) = \frac{1}{3} n + \frac{4}{3}

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