Find the refractive index of a medium if due speed of light in that medium is $2.25 \times 10^{8} m / s$ .

0.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.33

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.33

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 1.33
We know that the refractive index of a medium = $\frac{c}{v_{m}}$
where, $v_{m}$ = speed of light in the medium $= 2.25 \times 10^{8} m / s$
and, $c =$ speed of light $= 3 \times 10^{8} m / s$
Therefore, Refractive index of medium $= \frac{3 \times 10^{8}}{2.25 \times 10^{8}} = 1.33$

Suggest Corrections

Similar questions

X

1.5 \times 10^{8} m / s

3 \times 10^{8} m / s

X

1.5 \times 10^{8} m / s

Solve:

(1) The speed of light in a transparent medium is 2.4 × 10⁸ m/s. Calculate absolute refractive index of the medium.

(2) The speed of light in water and glass is 2.2 × 10⁸ m/s and 2 × 10⁸ m/s, respectively. What is the refractive index of −

(a) water w.r.t. glass

(b) glass w.r.t. water.

(3) Refractive index of water is 4/3 and speed of light in air is 3×10⁸ m/s. Find speed of light in water.

1.5 \times 10^{8} m / s

μ

Join BYJU'S Learning Program