Find the refractive index of the liquid from the given figure.
√32
Angle of incidence and the angle of refraction are the angles which the incidence ray and the refracted ray make with the normal.
∴ Angle of incidence = 90∘−30∘=60∘
Angle of refraction = 90∘−45∘=45∘
.
So, i=60∘ and r=45∘
By Snell's law
sin i μ1=sin r μ2
or sin 60∘×1=sin 45∘×μ2 [∵ Refractive index of air is taken as 1]
or, μ2=sin 60sin 45=√321√2=√32
Hence, correct option is A.