Applying the identity in (a+b)2=a2
(a+b)2=a2
a2+b2+2ab=a2
b(b+2a)=0
b=0 or b=−2a
In the adjoining figure, if BC = a, AC = b, AB = c and ∠CAB=120∘, then the correct relation is-
In the adjoining figure, if BC=a, AC=b, AB=c and ∠CAB=120∘, then the correct relation is