Find the relation between acceleration of A(a) and acceleration of B(b) in the figure shown
A
a=bsinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a=bcosθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a=btanθ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
a=bcotθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Ca=btanθ From the constraint relation, the accelerations of the bodies in perpendicuar direction to the point of contact of the surfaces should be same.