Find the relation between acceleration of A(a) and acceleration of B(b) in the figure shown
A
a=bsinθ
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B
a=bcosθ
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C
a=btanθ
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D
a=bcotθ
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Solution
The correct option is Ca=btanθ From the constraint relation, the accelerations of the bodies in perpendicuar direction to the point of contact of the surfaces should be same.
So, from the figure we have, acosθ=bsinθ⇒a=btanθ