Find the relation between the acceleration of sphere (a) and acceleration of wedge (b) in the figure shown
A
a=bcosαcosβ
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B
a=bcosβcosα
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C
a=bcos2βsinα
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D
a=bsin2βcosα
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Solution
The correct option is Aa=bcosαcosβ The acceleration of the bodies perpendicular to the surface of contact are equal as both the bodies should not loose the contact with each other, hence by figure we have ⇒acosβ=bcosα