Given that the points A(x,y) ,B(-5,7) and C(-4,5) are collinear.
So, the area of triangle formed by their vertices is 0.
Therefore,
12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]=0
⇒ 12[x(7−5)−5(5−y)−4(y−7)]=0
⇒ 12[x(2)−5(5−y)−4(y−7)]=0
⇒ 2x−25+5y−4y+28=0
⇒ 2x+y+3=0
y=−2x−3
which is the required relation between x and y i.e., y=−2x−3.