Find the relative molecular mass of methyl alcohol $(C H_{3} O H)$ , if $160 g m$ of the alcohol on vaporization has a volume of $112$ litres at STP.

16 g m

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32 g m

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160 g m

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80 g m

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Solution

The correct option is D $32 g m$
As we know, one mole of a gaseous substance occupies $22.4$ litres volume.

Mole $= \frac{w}{M}$

$\frac{160}{M} = \frac{112}{22.4}$

$M = 32 g m$
Also, molar mass $= 2 \times v a p o u r d e n s i t y$
Therefore, vapour density $= 16 g m$

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Q. Methyl alcohol,

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is:

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Find the relative molecular mass of methyl alcohol (CH3OH), if 160gm of the alcohol on vaporization has a volume of 112 litres at STP.

The correct option is D 32gmAs we know, one mole of a gaseous substance occupies 22.4 litres volume.Mole =wM160M=11222.4M=32gmAlso, molar mass =2×vapourdensityTherefore, vapour density =16gm

Find the relative molecular mass of methyl alcohol $(C H_{3} O H)$ , if $160 g m$ of the alcohol on vaporization has a volume of $112$ litres at STP.

The correct option is D $32 g m$
As we know, one mole of a gaseous substance occupies $22.4$ litres volume.

Mole $= \frac{w}{M}$

$\frac{160}{M} = \frac{112}{22.4}$

$M = 32 g m$
Also, molar mass $= 2 \times v a p o u r d e n s i t y$
Therefore, vapour density $= 16 g m$