Find the remainder and quotient when $x^{3} + x^{2}$ - 9x - 9 is divided by (x + 1)

Quotient = $x^{2}$ - 9

Remainder = 0

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Quotient = $x^{2}$ - 9

Remainder = 9

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Quotient = $4 x^{2}$ + 5

Remainder = 5

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Quotient = $9 x^{2}$ + 4

Remainder = 8

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Solution

The correct option is A
Quotient = $x^{2}$ - 9

Remainder = 0

Use long division

The remainder = 0

Quotient = $x^{2}$ - 9

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Similar questions

3 x^{2} - x^{3} - 3 x + 5

x - 1 - x^{2}

When $x^{4} + x^{3} - 2 x^{2} + x + 1$ is divided by x-1, the remainder is 2 and the quotient is q(x). Find q(x).

x^{3} - 3 x + 4

x - 4 .

x^{4} + x^{3} - 2 x^{2} + x + 1

x - 1

2

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